A long solenoid carries a current of 2.0 A , and the magnetic intensity H at its centre is determined to be 1500 A m ⁻¹ . Calculate the number of turns per centimetre of the solenoid.

Step-by-step solution

The magnetic intensity H at the centre of a long solenoid is given by: H = nI where n is the number of turns per unit length and I is the current. Given H = 1500 A m ⁻¹ and I = 2.0 A . Substituting the values: 1500 = n 2.0 n = 750 turns m ⁻¹ To find the number of turns per centimetre, we divide by 100 : n = 750 100 = 7.5 turns cm ⁻¹