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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Magnetic Properties of Matter

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Magnetic Properties of Matter

Suppose each iron atom possesses a permanent magnetic moment of 2...

Suppose each iron atom possesses a permanent magnetic moment of 22 Bohr magnetons (where 11 Bohr magneton equals 9.27imes10−24extAm29.27 imes 10^{-24} ext{ A m}^2). The density of atoms in iron is given as 8.52imes1028extatomsm−38.52 imes 10^{28} ext{ atoms m}^{-3}. Determine the maximum magnetization II in a long cylinder of iron.

Options

  1. A3.16imes106extAm−13.16 imes 10^6 ext{ A m}^{-1}
  2. B7.90imes105extAm−17.90 imes 10^5 ext{ A m}^{-1}
  3. C1.58imes106extAm−11.58 imes 10^6 ext{ A m}^{-1}
  4. D1.58imes105extAm−11.58 imes 10^5 ext{ A m}^{-1}

Correct answer

C. 1.58imes106extAm−11.58 imes 10^6 ext{ A m}^{-1}

Step-by-step solution

Maximum magnetization is achieved when all atomic magnetic moments are perfectly aligned parallel to each other.

The maximum magnetization II is the total magnetic moment per unit volume, given by:

I=n×mI = n \times m

where nn is the number of atoms per unit volume and mm is the magnetic moment of each atom.

Substituting the given values:

I=(8.52×1028)×(2×9.27×10−24)I = (8.52 \times 10^{28}) \times (2 \times 9.27 \times 10^{-24})

I=8.52×18.54×104I = 8.52 \times 18.54 \times 10^4

I=157.96×104I = 157.96 \times 10^4

I≈1.58×106 A m−1I \approx 1.58 \times 10^6 \text{ A m}^{-1}
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