Suppose each iron atom possesses a permanent magnetic moment of 2 Bohr magnetons (where 1 Bohr magneton equals 9.27 imes 10⁻²⁴ ext A m ^2 ). The density of atoms in iron is given as 8.52 imes 10²⁸ ext atoms m ⁻³ . Determine the maximum magnetization I in a long cylinder of iron.

Step-by-step solution

Maximum magnetization is achieved when all atomic magnetic moments are perfectly aligned parallel to each other. The maximum magnetization I is the total magnetic moment per unit volume, given by: I = n m where n is the number of atoms per unit volume and m is the magnetic moment of each atom. Substituting the given values: I = (8.52 10²⁸) (2 9.27 10⁻²⁴) I = 8.52 18.54 10^4 I = 157.96 10^4 I 1.58 10^6 A m ⁻¹