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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
The Special Theory of Relativity

Concepts Of Physics MCQ Edition [Volume 2] · Physics · The Special Theory of Relativity

Measured at rest, a rod has an exact length of 1 m . Determine its...

Measured at rest, a rod has an exact length of 1 m1 \text{ m}. Determine its length when it travels at a speed of 3×106 m s−13 \times 10^6 \text{ m s}^{-1}.

Options

  1. A1.00010 m1.00010 \text{ m}
  2. B0.99990 m0.99990 \text{ m}
  3. C1.00005 m1.00005 \text{ m}
  4. D0.99995 m0.99995 \text{ m}

Correct answer

D. 0.99995 m0.99995 \text{ m}

Step-by-step solution

The rest length of the rod is L0=1 mL_0 = 1 \text{ m}.

The speed of the rod is v=3×106 m s−1v = 3 \times 10^6 \text{ m s}^{-1}.

The speed of light is c=3×108 m s−1c = 3 \times 10^8 \text{ m s}^{-1}.

According to the special theory of relativity, the contracted length LL is given by:

L=L01−v2c2L = L_0 \sqrt{1 - \dfrac{v^2}{c^2}}

Substituting the given values:

L=1×1−(3×1063×108)2L = 1 \times \sqrt{1 - \left(\dfrac{3 \times 10^6}{3 \times 10^8}\right)^2}

L=1−(10−2)2L = \sqrt{1 - (10^{-2})^2}

L=1−10−4L = \sqrt{1 - 10^{-4}}

Using the binomial approximation (1−x)1/2≈1−x2(1 - x)^{1/2} \approx 1 - \dfrac{x}{2} for x≪1x \ll 1:

L≈1−10−42L \approx 1 - \dfrac{10^{-4}}{2}

L≈1−0.00005L \approx 1 - 0.00005

L=0.99995 mL = 0.99995 \text{ m}
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