The provided figure illustrates the intensity–wavelength relations of X-rays emitted from two different Coolidge tubes. The solid curve corresponds to tube A , where the potential difference between the target and the filament is V_A and the atomic number of the target material is Z_A . For the other tube, the respective quantities are V_B and Z_B . Consequently,

Step-by-step solution

From the given graph, the cut-off wavelength (minimum wavelength) for tube A (solid curve) is smaller than that for tube B (dashed curve): _ min, A The cut-off wavelength is given by _ min = hc eV . Since _ min is inversely proportional to the accelerating voltage V , we get: V_A > V_B Also, from the graph, the wavelength of the K_ peak for tube A is greater than that for tube B: _ K_ , A > _ K_ , B According to Moseley's law, the wavelength of characteristic X-rays is related to the atomic number Z by 1 (Z - b)^2