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The sum of present ages of 3 persons is 72 yrs. Seven years ago, their ages were in the ratio (4: 6: 7 ). What are their present ages in years?

Options

  1. A(20,30,22 )
  2. B(22,24,26 )
  3. C(19,25,28 )
  4. D(17,25,30 )

Correct answer

C. (19,25,28 )

Step-by-step solution

Given: The sum of present ages of 3 persons (=72 ) years Seven years ago, their ages were in the ratio (4: 6: 7 ) Formula Used: Sum of present ages (=x+y+z ) Ratio relation: ((x-7):(y-7):(z-7)=4: 6: 7 ) Calculation: Let the ages of three persons seven years ago be (4 k , 6 k ), and 7 k respectively. Then, their present ages are ((4 k+7),(6 k+7) ), and ((7 k+7) ). According to the given condition: ( aligned & (4 k +7)+(6 k +7)+(7 k +7)=72 & 4 k +6 k +7 k +21=72 & 17 k +21=72 & 17 k =72-21 & 17 k =51 & k =51 / 17 & k

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