English and Logical Reasoning Prep Guide
- Exam
- English and Logical Reasoning Prep Guide
- Subject
- Logical Reasoning
- Chapter
- Logical Deduction
English and Logical Reasoning Prep Guide · Logical Reasoning · Logical Deduction
Directions: In these questions, relationship between different...
Directions: In these questions, relationship between different elements is shown in the statement. The statements are followed by two conclusions. Choose the correct Answer given below:
Statements: A > B = S , & E& ≥& B > J ,& & & H < S& ≤ E ,& A > S ≥ TConclusions:& E > T,& & & E = T& ,& & A > J
Options
- ANone of the conclusions follow
- BOnly conclusion I and either conclusion II or II follow
- CEither conclusion I or II follows
- DOnly conclusion III and either conclusion I or II follow
Correct answer
D. Only conclusion III and either conclusion I or II follow
Step-by-step solution
Statements:& A > B = S , & E& ≥& B > J ,& & & H < S& ≤ E ,& A > S ≥ T
Conclusions:& E > T,& & & E = T& ,& & A > J
For conclusion I: E > T
From statements III and IV, we get:
T ≤ S& ≤ E
Here, common sign between T and E is '≤'. Thus T ≤ E or E ≥ T.
Also, From statements I, III and IV, we get:
& E& ≥ B = S ≥ T
Here, common sign between E and T is '≥'. Thus T ≤ E or E ≥ T.
Hence conclusion I does not follow individually.
For conclusion II: E = T
From statements III and IV, we get:
T ≤ S& ≤ E
Here, common sign between T and E is '≤'. Thus T ≤ E or E ≥ T.
Also, From statements I, III and IV, we get:
& E& ≥ B = S ≥ T
Here, common sign between E and T is '≥'. Thus T ≤ E or E ≥ T.
From statements III and IV, we get:
T ≤ S& ≤ E
Here, common sign between T and E is '≤'. Thus T ≤ E or E ≥ T.
Also, From statements I, III and IV, we get:
& E& ≥ B = S ≥ T
Here, common sign between E and T is '≥'. Thus T ≤ E or E ≥ T.
Hence conclusion II does not follow individually.
For conclusion III: A > J
From statements I and II, we get:
A > B > J
Here, the common sign between A and J is '>'. Thus A > J.
Hence conclusion III follows.
Combining conclusions I and II:
As the final conclusion is E ≥ T, so if we combine both the conclusions I and II i.e. E > T and E = T, we get E ≥ T.
Thus either conclusion I or conclusion II follows.
Therefore, either conclusion I or II and conclusion III follow.
Hence option D is correct.
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