i) There are 9 friends A, B, C, D, E, F, G, H seated in a circle...

To solve this circular arrangement, we first identify the fixed chain formed by the constraints: - A's Neighbors: Since $A$ is adjacent to both $C$ and $H$, the sequence is $C-A-H$. - Placing B & E: $B$ is (2^{\text {nd }}) to the right of $H$, and $E$ is (3^{\text {rd }}) to the right of $C$. This forces $E$ between $H$ and $B$, resulting in: $C-A-H-E-B$. - Adjacency: $F$ must sit next to $B(C-A-H-E-B-F)$. The remaining 3 seats belong to $D, G$ (adjacent), and an unknown 9th person. 1. (2^{\text {nd }}) to left of A: This seat depends on the 9 th person's position. (D) Cannot be determined. 2. (3^{\text {rd }}) to left of C: Occupied by the unfixed $D / G / 9 t h$ group. (D) None of these. 3. C's position wrt E: In a 9-person circle, $C$ is 3 seats left of $E$, which is equivalent to (A) (5^{\text {th }}) to the right.