An optically active organic compound (A) has the molecular formula C ₇ H ₁₀ . On catalytic hydrogenation with H ₂/ Pt , it forms an optically inactive compound (B). Identify compound (A).

Step-by-step solution

For compound (A) to be optically active, it must possess a chiral center. In Option (A), the structure is 3-ethylpent-1-en-4-yne. The central carbon atom is bonded to four different groups: -H , -CH₂CH₃ (ethyl), -CH=CH₂ (vinyl), and -C CH (ethynyl). Since all four groups are different, the molecule is chiral and optically active. Its molecular formula is C₇H₁₀ . Upon catalytic hydrogenation with H₂/Pt , the unsaturated vinyl and ethynyl groups are completely reduced to saturated ethyl groups. The resulting product