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Highly selective Backlog Qs for JEE MainMathematicsPermutation and Combination

What is the number of ways in which an examiner can assign 10 marks to 4 questions, giving not less than 2 marks to any questions?

Options

  1. A4
  2. B6
  3. C10
  4. D16

Correct answer

C. 10

Step-by-step solution

x₁+x₂+x₃+x₄=10 x_ i 2 (x₁-2 )+ (x₂-2 )+ (x₃-2 )+ (x₄-2 )=2 array llll y ₁ & y ₂ & y ₃ & y ₄ array y ₁+ y ₂+ y ₃+ y ₄=2 ; y _ i 0 N.O.W = ²⁺⁴⁻¹ C _ 4-1 = ⁵ C ₃=10

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