A person invites a party of 10 friends at dinner and place them so that 4 are on one round table and 6 on the other round table. The number of ways in which he can arrange the guests is

Step-by-step solution

Selection of 6 guests =10 C 6 Permutation of 6 on round table =5 ! Permutation of 4 on round table =3 ! Then, total number of arrangements =10 C 6.5 ! .3 ! = (10) ! 6 ! 4 ! 5 ! .3 != (10) ! 24