Highly selective Backlog Qs for JEE MainMathematicsQuadratic Equation

Each of the roots of the equation x^3-6 x^2+6 x-5=0 are increased by h . So that the new transformed equation does not contain x^2 term, then h is equal to

Options

A1
B2
C1 2
D1 3

Correct answer

B. 2

Step-by-step solution

Given equation is x^3-6 x^2+6 x-5=0x of this equation replaced by x+h . gathered (x+h)^3-6(x+h)^2+6(x+h)-5=0 x^3+h^3+3 x^2 h+3 x h^2-6 (x^2+h^2+2 x h ) +6 x+6 h-5=0 gathered Since, coefficient of x^2=0 3 h-6=0 h=2

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