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JEE Main

Exam: JEE Main
Subject: Physics
Chapter: Kinetic Theory of Gases

JEE Main · Physics · Kinetic Theory of Gases

The equation of state for 5 ~g of oxygen at a pressure P and...

The equation of state for

5 \mathrm{~g}

of oxygen at a pressure

P

and temperature

T

, when occupying a volume

V

, will be: (where

R

is the gas constant)

Options

A $P V=(5 / 32) R T$
B $P V=5 R T$
C $P V=(5 / 2) R T$
D $P V=(5 / 16) R T$

Correct answer

A. $P V=(5 / 32) R T$

Step-by-step solution

We know that

P V=\underline{n} R T\begin{gathered} \therefore n=\frac{m}{\text { moleculer mass }}=\frac{5}{32} \\ \Rightarrow \quad P V=\left(\frac{5}{32}\right) R T \end{gathered}

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