Highly selective Backlog Qs for JEE MainPhysicsLaws of Motion
Three blocks are placed at rest on a smooth inclined plane with force acting on m 1 parallel to the inclined plane. Find the contact force between m 2 and m 3
Options
- Am 1 + m 2 + m 3 m 3
- Bm 3 F m 1 + m 2 + m 3
- CF - m 1 + m 2 g
- DF
Correct answer
B. m 3 F m 1 + m 2 + m 3
Step-by-step solution
F = m 1 + m 2 + m 3 g sin  θ .... (1) N = m 3 g sin  θ .... (2) Dividing Eq. (2) by Eq. (1), we get N = m 3 F m 1 + m 2 + m 3