A body of mass 3 ~kg is under a constant force which causes a displacement s in metres in it, given by the relation s= 1 3 t^2 , where t is in seconds. Work done by the force in 2 seconds is:

Step-by-step solution

It is given that: s= t^2 3 Differentiating w.r.t. t we have U= d s d t = 2 t 3 Again differentiating w.r.t. t we have a= d^2 s d t^2 = 2 3 Now W = F d s= mads aligned & = m 2 3 2 t 3 d t & = 4 9 m t d t W & = 4 9 m [ t^2 2 ]₀^2 & = 4 9 3 2= 8 3 ~J aligned