Highly selective Backlog Qs for JEE MainPhysicsWork, Power and Energy
A particle of mass M and charge q is released from rest in a region of uniform electric field magnitude E . After a time t , the distance travelled by the charge is S and the kinetic energy attained by the particle is T . Then, the ratio T / S
Options
- Aremains constant with time t
- Bvaries linearly with the mass M of the particle
- Cis independent of the charge q
- Dis independent of the magnitude of the electric field E
Correct answer
A. remains constant with time t
Step-by-step solution
Given, mass of the particle =M . Charge on the particle =q Electric field =E Initial velocity, u=0 Acceleration, a= F M = q E M :.Distance travelled in electric field, S=u t+ 1 2 a t² S= 1 2 ( q E M ) t² Also, kinetic energy T= 1 2 M ( q E t M )² So, T S = 1 2 M ( q E t M )² 1 2 ( q E M ) t² =q E Ratio of T S remains constant with time t.