A particle is acted upon by a force F which varies with position x as shown in figure. If the particle at x = 0 has kinetic energy of 25 J, then the kinetic energy of the particle at x = 16 m is

Step-by-step solution

Work done W = Area under F-x graph with proper sign W = Area of triangle ABC + area of rectangle CDEF + Area of rectangle FGHI + Area of rectangle IJKL W ⁡ = 1 2 × 6 × 1 0 + 4 × - 5 + 4 × 5 + 2 × - 5 = 30 – 20 + 20 – 10 = 20 J ...(i) According to work energy theorem K f – K i = W or (K f ) x = 16 m – (K i ) x = 0 m = W (K f ) x = 16 m – (K i ) x = 0 m = 0 m + W = 25 J + 20 J (Using (i)) = 45 J