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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Basics of Mathematics

JEE Advanced · Mathematics · Basics of Mathematics

The solution of the equation |x-1|^ _3 x^2-2 _8 9 =(x-1)^7 is/are

The solution of the equation ∣x−1∣log⁡3x2−2log⁡89=(x−1)7|x-1|^{\log _3 x^2-2 \log _8 9}=(x-1)^7 is/are

Options

  1. A22
  2. B8181
  3. C13\frac{1}{\sqrt{3}}
  4. D33

Correct answer

B. 8181

Step-by-step solution

∵x−1>0\because x-1\gt0 Taking log both sides \left(\log _3 x^2-2 \log _x 9\right) \log (x-1)=7 \log (x-1)\Rightarrow x=81, \frac{1}{\sqrt{3}}, 2\therefore x \neq \frac{1}{\sqrt{3}}\therefore x=2,81
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