Most Important Selected Qs for JEE AdvancedMathematicsBinomial Theorem

Let (1+x^2 )^2(1+x)^n=A₀+A₁ x+A₂ x^2+ . If A₀, A₁, A₂ are in A.P. then the value of n is :

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Correct answer

B. 3

Step-by-step solution

gathered (1+x^2 )^2(1+x)^n= (1+2 x^2+x^4 ) ( ^n C₀+ ^n C₁ x+ ^n C₂ x^2+ ) = ^n C₀+ ^n C₁ x+ ( ^n C₂+2 . ^n C₀ ) x^2+ gathered Hence A₀=1 ; A₁= ^n C₁ ; A₂= ^n C₂+2 which are in A.P.

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