Let x be the elements of the set A= 1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120 and x₁, x₂, x₃ be positive integers and d be the number of integral solution of x₁ x₂ x₃=x then d is divisible by:

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Quantrex Academy · Accepted Answer

Correct answer: C. 20

aligned & x₁ x₂ x₃= 120 x^4 & x ₁ x ₂ x ₃ x ₄=120=2^3 3^1 5^1 & + + + =3,1,1 & ³⁺⁴⁻¹ C _ 4-1 ¹⁺⁴⁻¹ C _ 4-1 ¹⁺⁴⁻¹ C _ 4-1 & ^6 C ₃ ^4 C ₃ ^4 C ₃=320 aligned

Let x be the elements of the set A= 1,2,3,4,5,6,8,10,12,15,20,24,30,40,60,120 and x₁, x₂, x₃ be positive integers and d be the number of integral solution of x₁ x₂ x₃=x then d is divisible by:

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