All the 7 digit numbers containing each of the digits 1,2,3,4,5,6,7 exactly once and not divisible by 5 are arranged in the increasing order. Then -

Step-by-step solution

Total numbers which are not divisible by 5 are =6! 6=4320 Now when 1 or 2 or 3 occupies the 7^ th place, then the number of numbers =3 5! 5=1800 (last can be filled only in 5 ways) 1800^ th number in the list is 3765421 . when 1^ st two places are 41 then number of numbers =4! 4=96 1897^ th number in the list is 4213567 . with 42 aligned & number of numbers =4! 4=96 & Total so far =1800+192=1992 . aligned 1994^ th number in the list is 4312576 . 1^ st three places are filled as 4312 . . . aligned & number of number