A player throws an ordinary dice, whenever he throws 1 , he gets an additional throw. Then probability to get sum of score n is

Step-by-step solution

Score of 5 can be obtained as 5 or (1,4) or (1,1,3) or (1,1,1,2)P( scoring 5 )= 1 6 + 1 6^2 + 1 6^3 + 1 6^4 similarly P( scoring 6 )= 1 6 + 1 6^2 + 1 6^3 + 1 6^4 + 1 6^5 P( scoring 7 )= 1 6^2 + 1 6^3 + 1 6^4 + 1 6^5 + 1 6^6 P (scoring 1 ) is impossible event