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Most Important Selected Qs for JEE AdvancedMathematicsQuadratic Equation

If a x^2+b x+c=0 has no real root and a+b+c 0 then

Options

  1. A4 a-2 b+c 0
  2. B4 a-2 b+c 0
  3. C13 a+5 b+2 c 0
  4. D5 b-25 a-c 0

Correct answer

D. 5 b-25 a-c 0

Step-by-step solution

Let f(x)=a x^2+b x+c and f(1)=a+b+c 0 f(x) 0 for all x R f(-2) 0 4 a-2 b+c 0 Again f(3)+f(2) 0 13 a+5 b+2 c 0 Also f (-5) 0 25 a -5 ~b + c 0 5 ~b -25 a - c 0

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