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Most Important Selected Qs for JEE AdvancedMathematicsVector Algebra

A line passes through two points whose position vectors are i + j -2 k and i -3 j + k . The position vector of a point on it at a unit distance from the first point is -

Options

  1. A1 5 (5 i + j -7 k )
  2. B1 5 (4 i +9 j -13 k )
  3. C1 5 (6 i + j -7 k )
  4. D1 5 (5 i +9 j -13 k )

Correct answer

D. 1 5 (5 i +9 j -13 k )

Step-by-step solution

a = i + j -2 k , b = i -3 j + k p - a = ( b - a )= (-4 j +3 k )| p - a |= 16+9 25 ^2=1 = 1 5 p = a + ( b - a )= [ array l 1 5 (5 i + j -7 k ) 1 5 (5 i +9 j -13 k ) array .

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