Most Important Selected Qs for JEE AdvancedMathematicsVector Algebra
Let a , b and c be three unit vectors such that | a + b + c |= 3 and ( a b ) ( b c )+( b c ) ( c a )+( c a ) ( a b )= . Which of the following are CORRECT ?
Options
- AThe maximum value of is 0
- BIf is maximum then the volume of parallelepiped determined by a , b and c is 3
- CIf is maximum then the value of |(2 a +3 b +4 c ) ( a b +5 b c +6 c a )| is 32 .
- DNone of these
Correct answer
C. If is maximum then the value of |(2 a +3 b +4 c ) ( a b +5 b c +6 c a )| is 32 .
Step-by-step solution
aligned & ( a b ) ( b c )=( b c )( a b )- a c & ( b c ) ( c a )=( a c )( b c )- a b & ( c a ) ( a b )=( a b )( a c )- b c aligned Given that aligned & | a + b + c |= 3 ( a + b + c ) ( a + b + c )=3 a b + b c + c a =0 & =( a b ) ( b c )+( b c )( c a )+( c a )( a b )- a b - b c - c a & =( a b ) ( b c )+( b c )( c a )+( c a )( a b ) & 0[ since , x+y+z=0, x y+y z+ xx 0] & _ =0 only when a b = b c = a c =0 & a b , b c and c a & (2 a +3 ~b +4 c ) ( a b +5 ~b c +6 c a ) & =10 a ( b c )+18 ~b ( c a )+4 c ( a b )=32 aligned