Most Important Selected Qs for JEE AdvancedMathematicsVector Algebra
A parallelopiped is formed using three non-collinear vectors, a , b and c with fixod magnitudes. Angles between any of the vector with normal of the plane determined by the other two is and volume of the parallelopiped is T and its surface area is Y . If Y T =4 ( 1 | a | + 1 | b | + 1 | c | ) then:
Options
- A^2 + = 3 4
- B^2 + ^4 = 21 16
- C^2 + = 3+2 3 4
- D^2 + ^4 = 5 16
Correct answer
B. ^2 + ^4 = 21 16
Step-by-step solution
aligned & Y= surface area =2 ( | b c | [ a b c ] + | c a | [ a b c ] + | a b | [ a b c ] ) & =2 ( 1 | a | + 1 | b | + 1 | c | ) & 2 =4 = 1 2 aligned