Most Important Selected Qs for JEE AdvancedPhysicsLaws of Motion
A uniform cube of mass 4 kg and side 30 cm is placed on a frictionless horizontal surface. A vertical force F is applied to the edge as shown in the figure. Choose the most appropriate option(s). (take . g =10 ~m / s ^2 )
Options
- ACube will move in the upward direction if F 40 ~N
- BCube will not perform any type of translation or rotation motion if 10 ~N F 20 ~N
- Ccube will begin to perform rotational motion if 20 ~N F 40 ~N
- DNormal reaction applied by the surface shifts to a distance 5 cm from centre C of the cube if F =10 ~N
Correct answer
D. Normal reaction applied by the surface shifts to a distance 5 cm from centre C of the cube if F =10 ~N
Step-by-step solution
The correct answer is option A,B,C,D. Momentum of segment of mass dm and length d aligned & d p = dmu ( i + j ) & = u [ ~d i + d j ] & P = [ dx i + dy j ] & p = u [ ~d i + h j ] & P = u ~d ^2+ h ^2 & =1 1 3^2+4^2 =5 ~kg - m / s aligned