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Most Important Selected Qs for JEE AdvancedMathematicsApplication of Derivatives

A curve passes through (2,0) and the slope of tangent at any point (x, y) is x^2-2 x x R . The point of minimum ordinate on the curve where x>0 is (a, b) , then find the value of (a+6 b) .

Correct answer

2

Step-by-step solution

aligned f^ (x) & =x^2-2 x f(x) & = x^3 3 -x^2+c f(2) & =0 8 3 -4+c & =0 c & = 4 3 f(x) & = x^3 3 -x^2+ 4 3 aligned Minimum ordinate will be at x=2 aligned & f(2)= 8 3 -4+ 4 3 =0 & Point (a, b)=(2,0) & a+6 b=2 aligned

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