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Let | _ 2 30- | ₂ 9+ | ₄ 9- | _ 1 / 2 5||||=x . Then the smallest integer greater than or equal to x , is:

Correct answer

6

Step-by-step solution

aligned & | _ 2 30- | ₂ 9+ | ₂ 3- ₂ 5 |||= | _ 2 30- | ₂ 9+ ₂ 5- ₂ 3|| & = | _ 2 30- | ₂ 3+ ₂ 5||= | _ 2 30- ₂ 15 |= ₂ 60 & 5 < ₂ 60 < 6 aligned

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