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JEE Main 202311 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Polymers

JEE Main 2023 · 11 April · Evening Shift · Chemistry · Polymers

Given below are two statements: Statement I: Ethane at 333 to 343K...

Given below are two statements:
Statement I: Ethane at 333333 to 343K343K and 6−76 - 7 atm pressure in the presence of AlEt3{AlEt}_{3} and TiCl4{TiCl}_{4} undergoes addition polymerization to give LDP.
Statement II: Caprolactam at 533−543K533 - 543K in H2O{H}_{2}O through step growth polymerizes to give Nylon6Nylon6.

In the light of the above statements, choose the correct answer from the options given below:

Options

  1. AStatement I is false but Statement II is true
  2. BStatement I is true but Statement II is false
  3. CBoth Statement I and Statement II are true
  4. DBoth Statement I and Statement II are false

Correct answer

A. Statement I is false but Statement II is true

Step-by-step solution

Low Density Polyethylene is obtained by the polymerisation of ethene under high pressure of 1000−2000atm1000 - 2000atm at 350−570K350 - 570K in the presence of an initiator. High Density Polyethylene is obtained when polymerisation is done in the presence of Ziegler-Natta catalyst at 333−343K333 - 343K under 6−7atm6 - 7atm pressure. Nylon-6 is manufactured from the monomer called caprolactam. The monomer caprolactam is heated at 533−543K533 - 543Kin an inert atmosphere, it polymerises to give nylon-6.

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