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The number of odd proper divisors of 24300 is N +11 , then N is equal to

Correct answer

6

Step-by-step solution

24300=2^2 3^5 5^2 Number of odd divisors = the number of terms in (1+3+3^2+3^3+3^4+3^5 ) (1+5+5^2 )=6+6+6=18 This also includes the factor 1 . So the number of proper odd divisors =17

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