Die A has four red faces and two white faces, die B has two red and four white faces. A fair coin is tossed. If it shows head, then die A is rolled thrice, otherwise die B is rolled thrice. If the first two throws of die shows red face, the

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Die A has four red faces and two white faces, die B has two red and four white faces. A fair coin is tossed. If it shows head, then die A is rolled thrice, otherwise die B is rolled thrice. If the first two throws of die shows red face, then the probability of getting red face in third throw is a b (in lowest terms) then (a-1)^ b-3 is equal to

Quantrex Academy · Accepted Answer

Correct answer: 4

A event that die A was used in first two throws B event that die B was used in first two throws C event that next throws gives red face E event that first two throws give red faces aligned & P ( A E )= 1 2 ( 4 6 )^2 1 2 ( 4 6 )^2+ 1 2 ( 2 6 )^2 = 4 5 & P ( B E )= 1 5 P ( C E )= 3 5 & a=3, b=5 aligned

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