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Two dice are rolled and at the same time two coins are tossed. Given that one of the dice had shown a six and one of the coins has shown a heads, the probability that others will also show the same combination is p 33 , then p is equal to

Correct answer

1

Step-by-step solution

3 11=33 3 for HH , HT and TH and 11 for the cases when atleast one 6 appears So, required probability will be 1 33 (as there is only one way in which the required condition is satisfied)

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