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There are 4 urns. The first urn contains 1 white & 1 black ball, the second urn contains 2 white & 3 black balls, the third urn contains 3 white & 5 black balls & the fourth urn contains 4 white & 7 black balls. The selection of each urn is not equally likely. The probability of selecting i^ th urn is i^2+1 34 (i=1,2,3,4) . If we randomly select one of the urns & draw a ball, then the probability of ball being white

Correct answer

20

Step-by-step solution

aligned & U 1-1 W+1 B & U 2 2 W+3 B ; U 3 3 W+5 B ; U 4 4 W+7 B & P(W)= _ i=1 ^4 (u₁ ) P (w / u_i )= _ i=1 ^4 i^2+1 34 P (w / v_i )= 1^2+1 34 1 2 + 2^2+1 34 2 5 + 3^2+1 34 3 8 + 4^2+1 34 4 11 = 569 1496 aligned

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