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Most Important Selected Qs for JEE AdvancedPhysicsLaws of Motion

In the system shown in the figure, a bead of mass m can slide on the string. There is friction between the bead and the string. Block B has mass equal to twice that of the bead. The system is released from rest with length =18.75 ~m of the string hanging below the bead. Assuming the pulley and string to be massless. Find the distance (in meter) moved by the block B before the bead slips out of the thread.

Correct answer

6.25

Step-by-step solution

aligned & mg - T =m a ₁ & 2 mg -2 ~T =2 ma ₂ aligned So, a₁=a₂ Relative acceleration of bead with respect to end =3 a displacement of block x= 1 2 at ^2= 3 =6.25 ~m

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