Most Important Selected Qs for JEE AdvancedPhysicsNuclear Physics
The -decay of Po-210 nuclei (in ground state at rest) is accompanied by emission of two groups of alpha particles with kinetic energies 4.706 MeV and 4.50 MeV . Following the emission of these particles, the daughter nuclei are found in the ground state and excited states. Find energy of gamma photon emitted by excited nuclei. Give answer in KeV . Make the approximation, Massof daughter nuclide Massof -particle = Mas
Correct answer
210
Step-by-step solution
Po ²¹⁰ X ^*+ X + , where X ^* and X are excited daughter nuclide formed and daughter nuclide in ground state. X ^ X + , energy of -photon = E _ x ^ - E _ x = ( K _ x + K _ )- ( K _ x ^ + K _ ^ )= 210 206 ( ~K _ - K _ ^ ) [ Kx K = 4 206 = K _ x ^ K _ ^ ]=210 KeV