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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Basics of Mathematics

JEE Advanced · Mathematics · Basics of Mathematics

Paragraph: The loganthmic function is defined as _a x=y (a)^y=x...

Paragraph: The loganthmic function is defined as log⁡a\log _a\mathrm{x}=\mathrm{y}⇒(a)y=x\Rightarrow(\mathrm{a})^y=\mathrm{x} where x>0\mathrm{x}\gt0. a>0\mathrm{a}\gt0 and a≠1log⁡10x\mathrm{a} \neq 1 \log _{10} \mathrm{x} is called common logarithm, while log⁡ex\log _e \mathrm{x} is called natural logarithm where c is an irrational quantity whose approximate value is nearly 2.71log⁡ex2.71 \log _e x is written as ln⁡x\ln x. Where base of log⁡\log is not written then it is assumed to be 10 . i.e., \logx\logx means log⁡10X\log _{10} \mathrm{X}Question: Solution of the equation log⁡(x+1+1)log⁡(x−403)=3\frac{\log (\sqrt{x+1}+1)}{\log (\sqrt[3]{x-40})}=3, is

Options

  1. A3535
  2. B4848
  3. C9999
  4. Dnone of these

Correct answer

B. 4848

Step-by-step solution

log⁡10(x+1+1)=3log⁡10(x−40)13=3×13log⁡10(x−40)\log _{10}(\sqrt{x+1}+1)=3 \log _{10}(x-40)^{\frac{1}{3}}=3 \times \frac{1}{3} \log _{10}(x-40)⇒x+1+1=x−40⇒x=48,35∴x>40∴x=48\begin{aligned} & \Rightarrow \sqrt{x+1}+1=x-40 \\ & \Rightarrow x=48,35 \\ & \therefore x\gt40 \\ & \therefore x=48\end{aligned}$$
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