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JEE Advanced
Exam
JEE Advanced
Subject
Mathematics
Chapter
Basics of Mathematics

JEE Advanced · Mathematics · Basics of Mathematics

Paragraph: The loganthmic function is defined as _a x=y (a)^y=x...

Paragraph: The loganthmic function is defined as log⁡a\log _a\mathrm{x}=\mathrm{y}⇒(a)y=x\Rightarrow(\mathrm{a})^y=\mathrm{x} where x>0\mathrm{x}\gt0. a>0\mathrm{a}\gt0 and a≠1log⁡10x\mathrm{a} \neq 1 \log _{10} \mathrm{x} is called common logarithm, while log⁡ex\log _e \mathrm{x} is called natural logarithm where c is an irrational quantity whose approximate value is nearly 2.71log⁡ex2.71 \log _e x is written as ln⁡x\ln x. Where base of log⁡\log is not written then it is assumed to be 10 . i.e., \logx\logx means log⁡10X\log _{10} \mathrm{X}Question: Solution of the equation \left(\frac{\log x}{2}\right)^{(\log x)^2+\log x^2-2}=\log \sqrt{x}

Options

  1. A1010
  2. B10001000
  3. C1100\frac{1}{100}
  4. Dnone of these

Correct answer

C. 1100\frac{1}{100}

Step-by-step solution

Take log both the sides on base 10 ∴log⁡(log⁡10x2){(log⁡10x)2+2log⁡10x−2}\therefore \log \left(\frac{\log _{10} x}{2}\right)\left\{ \left(\log _{10}x\right)^2+2 \log _{10} x-2\right\}=\log \left(\frac{\log _{10} x}{2}\right) Let, log⁡10\log _{10}\mathrm{x}=\mathrm{t} and ∴log⁡(12)(t2+2t−2)=log⁡(t2) and ⇒t=2,1,−3\begin{aligned} \text{ and } \therefore \log \left(\frac{1}{2}\right) \left(t^2+2 \mathrm{t}-2\right)=\log \left(\frac{\mathrm{t}}{2}\right)\\ \text{ and } \Rightarrow \mathrm{t}=2,1,-3\end{aligned}
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