Most Important Selected Qs for JEE AdvancedMathematicsPermutation and Combination
Paragraph: The exponent of prime number p in n ! is given by [ n p ]+ [ n p ^2 ]+ . . or _ r =1 ^ [ n p ^ r ] where [x] is greatest integer less than or equal to x . On the basis of above information answer the following : Question: The number of zeros 3250 ! ends with is -
Options
- A807
- B811
- C806
- D812
Correct answer
D. 812
Step-by-step solution
Ans. (D) aligned & [ 3250 5 ]+ [ 3250 25 ]+ [ 3250 125 ]+ [ 3250 625 ]+ [ 3250 3125 ] & =650+130+26+5+1=812 aligned