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Most Important Selected Qs for JEE AdvancedPhysicsLaws of Motion

A bike of length having its centre of mass at the middle is to turn with constant speed v [here v is the speed of centre of mass of the bike]. To turn, the front wheel is rotated by an angle . The coefficient of friction between the tyres and the road is . Assuming the bike to be vertical and it does not skid, answer the following questions. The friction force acting on the bike

Options

  1. A2 mv ^2 ^2 4+ ^2
  2. B2 m v^2 ^2 2+ ^2
  3. Cm v^2 ^2 4+ ^2
  4. Dm v^2 ^2 4+ ^2

Correct answer

A. 2 mv ^2 ^2 4+ ^2

Step-by-step solution

If the bike does not slip, path of both the wheel must be parallel with its direction as shown in the figure. aligned & R ₁= / & R _ cm = ( 2 )^2+ R ₁^2 = 2 4+ ^2 & Net friction force f = mv ^2 R _ cm = 2 ~m v^2 4+ ^2 aligned

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