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Most Important Selected Qs for JEE AdvancedPhysicsNuclear Physics

Paragraph: A nucleus kept at rest in the free space, break up into two smaller nuclei of masses m and 2 m . Total energy generated in this fission is E . The bigger part is radioactive, emits five gamma ray photons in the direction of its velocity and finally comes to rest (given h =6.6 10⁻³⁴ ~J - s , m =1.00 10⁻²⁶ ~kg , E =3.63 10⁻⁸ mc ^2, c =3 10^8 ~m / s Question: The wavelength of the gamma ray is

Options

  1. A0.02 Å
  2. B0.03 Å
  3. C0.04 Å
  4. D0.05 Å

Correct answer

D. 0.05 Å

Step-by-step solution

Total energy released will be in released in form K. Energy. Let V be the velocity of smaller nucleus. aligned & 1 2 m v^2+ 1 2 (2 m) v^2 4 =E & 3 4 m v^2=E aligned aligned v & = 4 E 3 m = 4 3.63 10⁻⁸ m c^2 3 m & = 4 1.21 10⁻⁸ 9 10⁻¹⁶ & =6 1.1 10^4 6.6 10^4 ~m / s 2 m & v 2 =5 h aligned

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