Most Important Selected Qs for JEE AdvancedPhysicsNuclear Physics
Paragraph: Few atomic masses are given ₉₂²³⁸ U =238.05079 u , ₂^4 He =4.00260 u , ₉₀²³⁴ Th =234.04363 u ₁^1 H =1.007834, ₉₁²³⁷ ~Pa =237.065121 u . Answer the following questions on the basis of above data. Question: Spontaneous emission of a proton from ₉₂²³⁸ U is
Options
- Apossible
- Bimpossible
- Ccan't say
- Dnone of these
Correct answer
B. impossible
Step-by-step solution
If it emits proton spontaneously, the equation is not balanced in terms of atoms & mass number. ₉₂²³⁸ U ₉₁²³⁷ ~Pa + ₁^4 H m =(238.05079-237.065121-1.007834) u =-0.022165 u m is negative, so reaction is not spontaneous.