Most Important Selected Qs for JEE AdvancedPhysicsKinetic Theory of Gases
If a monoatomic gas undergoes a thermodynamic process for which its molar heat capacity is equal to the universal gas constant. What is the process in terms of V and T ?
Options
- AVT ^ -1 / 2 = constant
- BVT ^ 1 / 2 = constant
- CV ^2 ~T ^2= constant
- DVT = constant
Correct answer
B. VT ^ 1 / 2 = constant
Step-by-step solution
C=R d Q n d T =R nC _v dT + dW ndT = R Cv + pdV ndT = R pdV ndT =- R 2 [ C _ r =3 R / 2 ] R T V d V d T =- R 2 [ P n = R T v ] dV V =- dT 2 ~T ( VT ^ 1 / 2 )= constant VT ^ 1 / 2 = constant