Most Important Selected Qs for JEE AdvancedPhysicsLaws of Motion
A block of mass 2 kg is kept over a block of mass 8 kg as shown in the figure. A force F =14 ~N acts on the upper block. Match the physical quantities from List I with those in List II and select the correct answer using the code given below the lists. All values are in S.I. units:
Options
- Aarray llll 4 & 2 & 1 & 3 array
- Barray llll 2 & 4 & 1 & 3 array
- Carray llll 1 & 2 & 3 & 4 array
- Darray llll 2 & 4 & 3 & 1 array
Correct answer
D. array llll 2 & 4 & 3 & 1 array
Step-by-step solution
Slipping between 2 and 8 (P) a_ 2 ~kg = 14-12 2 =1 (Q) a _ 8 ~kg = 12-10 8 = 1 4 (R) 0.6 2 10=12