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JEE Advanced
Exam
JEE Advanced
Subject
Physics
Chapter
Magnetic Properties of Matter

JEE Advanced · Physics · Magnetic Properties of Matter

A jet plane is travelling west at 450 ~m / s . If the horizontal...

A jet plane is travelling west at 450 m/s450 \mathrm{~m} / \mathrm{s}. If the horizontal component of earth's magnetic field is 4×10−4 T4 \times 10^{-4} \mathrm{~T} and angle of dip is 30∘30^{{}^{{}^{\circ}}}, then the vertical component is

Options

  1. A3×10−4 T3 \times 10^{-4} \mathrm{~T}
  2. B4×10−4 T4 \times 10^{-4} \mathrm{~T}
  3. C2.3×10−4 T2.3 \times 10^{-4} \mathrm{~T}
  4. D12.308×10−4 T12.308 \times 10^{-4} \mathrm{~T}

Correct answer

C. 2.3×10−4 T2.3 \times 10^{-4} \mathrm{~T}

Step-by-step solution

Given, BH=4×10−4 TB_{H}=4 \times 10^{-4} \mathrm{~T} Angle of dip⁡,δ=30∘\operatorname{dip}, \delta=30^{{}^{{}^{\circ}}} We know that, tan⁡δ=BVBH⇒BV=BHtan⁡δ=4×10−4tan⁡30∘=43×10−4=2.3×10−4 T\begin{aligned} \tan \delta &=\frac{B_{V}}{B_{H}} \\ \Rightarrow \quad B_{V} &=B_{H} \tan \delta \\ &=4 \times 10^{-4} \tan 30^{{}^{{}^{\circ}}} \\ &=\frac{4}{\sqrt{3}} \times 10^{-4} \\ &=2.3 \times 10^{-4} \mathrm{~T} \end{aligned}
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