Most Important Selected Qs for JEE AdvancedMathematicsApplication of Derivatives
The curve, with the property that the projection of the ordinate on the normal is constant and has a length equal to 'a', is
Options
- Ax + a ( y ^2- a ^2 + y )= c
- Bx+ a ^2- y ^2 = c
- C(y-a)^2=c x
- Da y= ⁻¹(x+c)
Correct answer
A. x + a ( y ^2- a ^2 + y )= c
Step-by-step solution
Ordinate = PM . Let P ( x , y ) Projection of ordinate on normal = PN PN = PM = a (given) y 1+ ^2 =a y=a 1+ (y₁ )^2 d y d x = y^2-a^2 a a d y y^2-a^2 = d x a |y+ y^2-a^2 |=x+c