Find the number of positive integers n such that the highest power of 7 dividing n! is 8 .

Step-by-step solution

Power of 7 in n!= [ n 7 ]+ [ n 7^2 ]+ n 7 7 Let n=49 Power of 7 in n!=7+1=8n may equal to 49,50,51,52,53,5455 number of possible values of n=07