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Integers 1,2,3 . n where n >2 , are written on a board. Two numbers m , k such that 1 < m < n .1 < k < n are removed and the average of the remaining numbers is found to be 17 . What is the maximum sum of the two removed numbers?

Correct answer

51

Step-by-step solution

aligned & n(n+1) 2 -(2 n-1) n-2 31 & n=32,33,34 & case- 1, n=32 aligned aligned & n(n+1) 2 -p (n-2) =17 n(n+1) 2 -17(n-2)=p & p=18 & case- 2, n=33 p=34 & case- 3, n=34 p=51 & Maximum sum =51 aligned

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