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Olympiad workbook
Exam
Olympiad workbook
Subject
IOQM
Chapter
Straight Lines

Olympiad workbook · IOQM · Straight Lines

Let A B C D be a rectangle in which A B+B C+ C D=20 and A E=9 where...

Let ABCDA B C D be a rectangle in which AB+BC+CD=20A B+B C+ C D=20 and AE=9A E=9 where EE is the mid-point of the side BCB C. Find the area of the rectangle.Let A B C D be a rectangle in which A B+B C+ C D=20 and A E=9 where E is the mid-point of the side B C . Find the area

Correct answer

19

Step-by-step solution

Let A B C D be a rectangle in which A B+B C+ C D=20 and A E=9 where E is the mid-point of the side B C . Find the area
2x+y=20y=20−2x...(i) In △ABE\begin{aligned} & 2 x+y=20 \\ & y=20-2 x ...(i)\\ & \text { In } \triangle A B E \end{aligned} x2+(y2)2=92x^2+\left(\frac{y}{2}\right)^2=9^2...(ii) Using (i) in (ii) x2+(20−2x2)2=81x2+(10−x)2=812x2−20x+19=0x=20±400−4×2×192×2x=10±622\begin{aligned} & x^2+\left(\frac{20-2 x}{2}\right)^2=81 \\ & x^2+(10-x)^2=81 \\ & 2 x^2-20 x+19=0 \\ & x=\frac{20 \pm \sqrt{400-4 \times 2 \times 19}}{2 \times 2} \\ & x=\frac{10 \pm \sqrt{62}}{2} \end{aligned} From (i) ⇒y=20−2(10±622)y=10∓62\begin{aligned} \Rightarrow \quad y & =20-2\left(\frac{10 \pm \sqrt{62}}{2}\right) \\ y & =10 \mp \sqrt{62} \end{aligned}  Area of rectangle =xy=12(10±62)(10∓62)=100−622=19\begin{aligned} \text { Area of rectangle }=x y & =\frac{1}{2}(10 \pm \sqrt{62})(10 \mp \sqrt{62}) \\ & =\frac{100-62}{2} \\ & =19\end{aligned}
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