In the L R circuit shown in figure, switch S is closed at time t=0...

In the

L R

circuit shown in figure, switch

S

is closed at time

t=0

, the charge that passes through the battery of emf E in one time constant is (e being the base of natural logarithm). In the L R circuit shown in figure, switch S is closed at time t=0 , the charge that passes through the battery of emf

In the L R circuit shown in figure, switch S is closed at time t=0 , the charge that passes through the battery of emf

Options

A $\frac{\mathrm{EL}}{\mathrm{eR}^2}$
B $\frac{\mathrm{EL}}{\mathrm{eR}}$
C $\frac{\mathrm{eER}^2}{\mathrm{~L}}$
D $\frac{\mathrm{EL}}{\mathrm{R}}$

Correct answer

A. $\frac{\mathrm{EL}}{\mathrm{eR}^2}$

Step-by-step solution

No solution

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