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An alpha particle with kinetic energy K approaches a stationary nucleus having atomic number Z . The distance of closest approach is b . Therefore the distance of closest approach for a nucleus of atomic number 2 Z is

Options

  1. Ab/2.
  2. B2 b .
  3. C2 b
  4. D4 b .

Correct answer

C. 2 b

Step-by-step solution

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